Kizungumza cha Kigame

Pata ukishika buti bila kufikiria kushikilia kushikilia kwenye kipande cha kichwani:

Ongeza mambo ya kina

Sasa tunataka kuongeza mambo ya kina kwenye mchezo.

Winga komponenti mpya kwenye eneo la mchezo. Ameingiza kwa rangi ya kijani, kipimo 10 mita, kipya 200 mita, na kuweka katika eneo ya kulia 300 mita, kwenye eneo la chini 120 mita.

haya kuwa na kusoma kila mtaani kwenye programu ya mchezo ya kipindi cha kila hati:

mikili

var myGamePiece;
var myObstacle;
function startGame() {
  myGamePiece = new component(30, 30, "red", 10, 120);
  myObstacle = new component(10, 200, "green", 300, 120);
  myGameArea.start();
}
function updateGameArea() {
  myGameArea.clear();
  myObstacle.update();
  myGamePiece.newPos();
  myGamePiece.update();
}

Tafakari yako

撞到障碍 = 游戏结束

在上面的例子中，当您碰到障碍物时什么也不会发生。在游戏中，这并不令人满意。

我们如何知道我们的红色方块是否撞到了障碍物？

在组件构造函数中创建一个新方法，用于检查该组件是否与另一个组件相撞。每次帧更新时都应调用此方法，每秒 50 次。

还要向 myGameArea 对象添加 stop() 方法，该方法会清除 20 毫秒的间隔。

mikili

var myGameArea = {
  canvas : document.createElement("canvas"),
  start : function() {
    this.canvas.width = 480;
    this.canvas.height = 270;
    this.context = this.canvas.getContext("2d");
    document.body.insertBefore(this.canvas, document.body.childNodes[0]);
    this.interval = setInterval(updateGameArea, 20);
  },
  clear : function() {
    this.context.clearRect(0, 0, this.canvas.width, this.canvas.height);
  },
  stop : function() {
    clearInterval(this.interval);
  }
}
function component(width, height, color, x, y) {
  this.width = width;
  this.height = height;
  this.speedX = 0;
  this.speedY = 0;
  this.x = x;
  this.y = y;
  this.update = function() {
    ctx = myGameArea.context;
    ctx.fillStyle = color;
    ctx.fillRect(this.x, this.y, this.width, this.height);
  }
  this.newPos = function() {
    this.x += this.speedX;
    this.y += this.speedY;
  }
  this.crashWith = function(otherobj) {
    var myleft = this.x;
    var myright = this.x + (this.width);
    var mytop = this.y;
    var mybottom = this.y + (this.height);
    var otherleft = otherobj.x;
    var otherright = otherobj.x + (otherobj.width);
    var othertop = otherobj.y;
    var otherbottom = otherobj.y + (otherobj.height);
    var crash = true;
    if ((mybottom < othertop) ||
    (mytop > otherbottom) ||
    (myright < otherleft) ||
    (myleft > otherright)) {
      crash = false;
    }
    return crash;
  }
}
function updateGameArea() {
  if (myGamePiece.crashWith(myObstacle)) {
    myGameArea.stop();
  } else {
    myGameArea.clear();
    myObstacle.update();
    myGamePiece.newPos();
    myGamePiece.update();
  }
}

Tafakari yako

Kuendeleza ngumu

Ngumu hauwezi kuhatarisha kama anasema, kwa hivyo tunataka anafikie kwenye uendo.

kila upatekezo tunahitaji kumwambia mabadiliko myObstacle.x athari ya uga:

mikili

function updateGameArea() {
  if (myGamePiece.crashWith(myObstacle)) {
    myGameArea.stop();
  } else {
    myGameArea.clear();
    myObstacle.x += -1;
    myObstacle.update();
    myGamePiece.newPos();
    myGamePiece.update();
  }
}

Tafakari yako

Ngumu zaidi

Je, tunaweza kuongeza ngumu zaidi?

Kwa hivyo, tunahitaji kitu kinachohesabu muda wa muda wa kwanza na kitu kinachofanya matukio kwa kipindi kilichotakiwa.

mikili

var myGameArea = {
  canvas : document.createElement("canvas"),
  start : function() {
    this.canvas.width = 480;
    this.canvas.height = 270;
    this.context = this.canvas.getContext("2d");
    document.body.insertBefore(this.canvas, document.body.childNodes[0]);
    this.frameNo = 0;
    this.interval = setInterval(updateGameArea, 20);
  },
  clear : function() {
    this.context.clearRect(0, 0, this.canvas.width, this.canvas.height);
  },
  stop : function() {
    clearInterval(this.interval);
  }
}
function everyinterval(n) {
  if ((myGameArea.frameNo / n) % 1 == 0) {return true;}
  return false;
}

Kama namba ya muda wa kwanza inatangulia kwa kipindi kilichotakiwa, kifaa everyinterval inaruhusiwa kwa true.

Kwanza, kama tunahitaji kuingia ngumu zaidi, ingia ngumu wengi kama mabaya.

Kwa hivi, tunahitaji kufanya mafanikio kwa programu updateGameArea.

mikili

var myGamePiece;
var myObstacles = [];
function updateGameArea() {
  var x, y;
  for (i = 0; i < myObstacles.length; i += 1) {
    if (myGamePiece.crashWith(myObstacles[i])) {
      myGameArea.stop();
      return;
    }
  }
  myGameArea.clear();
  myGameArea.frameNo += 1;
  if (myGameArea.frameNo == 1 || everyinterval(150)) {
    x = myGameArea.canvas.width;
    y = myGameArea.canvas.height - 200
    myObstacles.push(new component(10, 200, "green", x, y));
  }
  for (i = 0; i < myObstacles.length; i += 1) {
    myObstacles[i].x += -1;
    myObstacles[i].update();
  }
  myGamePiece.newPos();
  myGamePiece.update();
}

Tafakari yako

在 updateGameArea 函数中，我们必须循环遍历每个障碍物来查看是否发生碰撞。如果发生碰撞，updateGameArea 函数将停止，并且不再进行绘制。

updateGameArea 函数对帧进行计数，并每隔 150 帧添加一个障碍物。

kina kina kina kina upya

kwa kumaliza muda na kumekua mfuno ya kigame, tumeagiza upya ukubwa wa kina kina, kwa hivyo kikirafu chake cha kichwa cha kina kina haichangwa.

mikili

function updateGameArea() {
  var x, height, gap, minHeight, maxHeight, minGap, maxGap;
  for (i = 0; i < myObstacles.length; i += 1) {
    if (myGamePiece.crashWith(myObstacles[i])) {
      myGameArea.stop();
      return;
    }
  }
  myGameArea.clear();
  myGameArea.frameNo += 1;
  if (myGameArea.frameNo == 1 || everyinterval(150)) {
    x = myGameArea.canvas.width;
    minHeight = 20;
    maxHeight = 200;
    height = Math.floor(Math.random()*(maxHeight-minHeight+1)+minHeight);
    minGap = 50;
    maxGap = 200;
    gap = Math.floor(Math.random()*(maxGap-minGap+1)+minGap);
    myObstacles.push(new component(10, height, "green", x, 0));
    myObstacles.push(new component(10, x - height - gap, "green", x, height + gap));
  }
  for (i = 0; i < myObstacles.length; i += 1) {
    myObstacles[i].x += -1;
    myObstacles[i].update();
  }
  myGamePiece.newPos();
  myGamePiece.update();
}

Tafakari yako