طريقة intersection_update() لمجموعات بايثون
Masu
حذف العناصر التي لا توجد في المجموعتين x و y
x = {"apple", "banana", "cherry"} y = {"google", "microsoft", "apple"} x.intersection_update(y) print(x)
Kira da Wasan
intersection_update() method ke kawar da abin da ba a fiwata ba a cikin kungiyar sabuntawa na duk.
intersection_update() method da intersection() method na farko, saboda intersection() method ke samun kungiyar sabuntawa da ba a fiwata ba, amma intersection_update() method ke kawo kawar da abin da a kawo aiki daga kungiyar sabuntawa na asali.
Syntax
set.intersection_update(set1, set2 ... etc)
Param Value
Param | Kira |
---|---|
set1 | Mai Dauki. Don samun kungiyar sabuntawa da ake samun kuma a cikinta. |
set2 |
Optional. Don samun kungiyar sabuntawa da ake samun kuma a cikinta. Anfasi. A ke kiyasa kungiyar sabuntawa da yanzu kuma a kawo aiki. Kungiyar sabuntawa dake yin lafzai da koma. |
More Masu
Masu
Kiyasa 3 Kungiyar Sabuntawa, kungiyar sabuntawa da ake samun ta bar a cikin duk 3 kungiyar sabuntawa:
x = {"a", "b", "c"} y = {"c", "d", "e"} z = {"f", "g", "c"} x.intersection_update(y, z) print(x)