AJAX mtaani wa ASP
- Pya ja AJAX PHP
- Pya ja Database ya AJAX
AJAX 用于创建更具交互性的应用程序。
AJAX mtaani wa ASP
下面的例子演示:当用户在输入字段中键入字符时,网页如何与 web 服务器进行通信:
Mfano
请在下面的输入字段中键入字母 A-Z:
Jina:
Mazungumzo ya tafuta:
Muhtasari wa mivuno
Kwenye mivuno hivi, kama mtumishi anasaja heri kwenye eneo la kuingia, inafanywa kazi ya funetu ya "showHint()".
Funetu hii inasababisha kwa matukio ya onkeyup.
Hapa ni maelezo ya HTML:
Mfano
<html> <head> <script> function showHint(str) { if (str.length == 0) { document.getElementById("txtHint").innerHTML = ""; return; } else { var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { document.getElementById("txtHint").innerHTML = this.responseText; } }; xmlhttp.open("GET", "gethint.asp?q=" + str, true); xmlhttp.send(); } } </script> </head> <body> <p><b>Ingiza herufi A-Z katika kifungu cha chini:</b></p> <form> Jina:<input type="text" onkeyup="showHint(this.value)"> </form> <p>Mapendekezo ya utafutaji:<span id="txtHint"></span></p> </body> </html>
Muhtasari wa kipengele cha programu:
Kwanza, tazama kama kifungu cha ingia hauwezi kusikia (str.length == 0
);kama ni, ingiza kwa upofu maudhui ya txtHint na kumaliza muundo.
lakini, kama kifungu cha ingia hauwezi kusikia, tena:
- Kapisha, watengeneza mbinu wa XMLHttpRequest
- Kapisha, watengeneza muundo wa kufanya kazi ambao hutendeka kufanyika wakati server anasikia kwa kusema
- Tuma mkataba wa ingia kwenye ASP file kwenye server (gethint.asp)
- Tafadhali ingiza kati ya q katika gethint.asp
- str variable huanza kusimamia maudhui ya kifungu cha ingia
ASP file - "gethint.asp"
Hii ASP file inaangalia array ya jina, na kumshambulia kwenye mifungo wa kibuka kwa jina:
<% response.expires=-1 dim a(32) ingiza jina kwa kufill array a(1)="Ava" a(2)="Brielle" a(3)="Caroline" a(4)="Diana" a(5)="Elise" a(6)="Fiona" a(7)="Grace" a(8)="Hannah" a(9)="Ileana" a(10)="Jane" a(11)="Kathryn" a(12)="Laura" a(13)="Millie" a(14)="Nancy" a(15)="Opal" a(16)="Petty" a(17)="Queenie" a(18)="Rose" a(19)="Shirley" a(20)="Tiffany" a(21)="Ursula" a(22)="Victoria" a(23)="Wendy" a(24)="Xenia" a(25)="Yvette" a(26)="Zoe" a(27)="Angell" a(28)="Adele" a(29)="Beatty" a(30)="Carlton" a(31)="Elisabeth" a(32)="Violet" Get q parameter from URL q=ucase(request.querystring("q")) Check if all hints in the array, the length of q is greater than 0 if len(q)>0 then hint="" for i=1 to 30 if q=ucase(mid(a(i),1,len(q))) then if hint="" then hint=a(i) else hint=hint & " , " & a(i) end if end if next end if If hint is not found, output "no suggestion" or output the correct value if hint="" then response.write("no suggestion") else response.write(hint) end if %>
- Pya ja AJAX PHP
- Pya ja Database ya AJAX