VBScript DateDiff Function
Definition and Usage
The DateDiff function can return the number of intervals between two dates.
The DateDiff function is used to calculate the difference between two date-time values, with the calculation being date2 - date1.
If comparing years, disregard the values below the month; if comparing months, disregard the values below the day... and so on.
Note:The firstdayofweek parameter affects the calculations using the interval symbols 'w' and 'ww'.
Syntax
DateDiff(interval,date1,date2[,firstdayofweek[,firstweekofyear]])
Parameter | Description |
---|---|
interval |
Required. The unit of time used to calculate the time interval between date1 and date2. The following values can be used:
|
date1,date2 | Required. Date expression. Two dates to be used in the calculation. |
firstdayofweek |
Optional. Specifies the number of days in a week, i.e., the day of the week. The following values can be used:
|
firstweekofyear |
Optional. Specifies the first week of the year. The following values can be used:
|
Beispiel
Beispiel 1
document.write(Date & "<br />") document.write(DateDiff("m",Date,"12/31/2002") & "<br />") document.write(DateDiff("d",Date,"12/31/2002") & "<br />") document.write(DateDiff("n",Date,"12/31/2002"))
Ausgabe:
1/14/2002 11 351 505440
Beispiel 2
Bitte beachten Sie im folgenden Code, dass date1>date2:
document.write(Date & "<br />") document.write(DateDiff("d","12/31/2002",Date))
Ausgabe:
1/14/2002 -351
Beispiel 3
Wie viele Wochen (Start am Montag), bleiben zwischen dem aktuellen Datum und 10/10/2002 document.write(Date & "<br />") document.write(DateDiff("w",Date,"10/10/2002",vbMonday))
Ausgabe:
1/14/2002 38