VBScript DateDiff Function
Definition and Usage
The DateDiff function can return the number of time intervals between two dates.
The DateDiff function is used to calculate the difference between two date and time values, with the calculation method being date2 - date1.
If comparing years, ignore the values below the month; if comparing months, ignore the values below the day, and so on.
Note:The firstdayofweek parameter affects the calculation using the interval symbols 'w' and 'ww'.
Syntax
DateDiff(interval,date1,date2[,firstdayofweek[,firstweekofyear]])
Parameter | Description |
---|---|
interval |
Required. The unit of time interval between date1 and date2 to be calculated. The following values can be used:
|
date1,date2 | Required. Date expression. Two dates to be used in the calculation. |
firstdayofweek |
Optional. Defines the number of days in a week, that is, the day of the week. The following values can be used:
|
firstweekofyear |
Optional. Defines the first week of the year. The following values can be used:
|
Instance
Example 1
document.write(Date & "<br />") document.write(DateDiff("m",Date,"12/31/2002") & "<br />") document.write(DateDiff("d",Date,"12/31/2002") & "<br />") document.write(DateDiff("n",Date,"12/31/2002"))
Output:
1/14/2002 11 351 505440
Example 2
Please note that in the following code, date1>date2:
document.write(Date & "<br />") document.write(DateDiff("d","12/31/2002",Date))
Output:
1/14/2002 -351
Example 3
How many weeks (start on Monday), are left between the current date and 10/10/2002 document.write(Date & "<br />") document.write(DateDiff("w",Date,"10/10/2002",vbMonday))
Output:
1/14/2002 38