VBScript DateDiff Function
Definition and Usage
The DateDiff function can return the number of time intervals between two dates.
The DateDiff function is used to calculate the difference between two date and time values, with the calculation method being date2 - date1.
When comparing years, regardless of the value below the month, when comparing months, regardless of the value below the day, and so on.
Note:The firstdayofweek parameter affects the calculation using the interval symbols 'w' and 'ww'.
Syntax
DateDiff(interval,date1,date2[,firstdayofweek[,firstweekofyear]])
Parameter | Description |
---|---|
interval |
Required. The unit of time interval between date1 and date2 to be calculated. The following values can be used:
|
date1,date2 | Required. Date expression. Two dates that need to be used in the calculation. |
firstdayofweek |
Optional. Specifies the number of days in a week, that is, which day of the week it is. The following values can be used:
|
firstweekofyear |
Optional. Specifies the first week of the year. The following values can be used:
|
Exempel
Exempel 1
document.write(Date & "<br />") document.write(DateDiff("m",Date,"12/31/2002") & "<br />") document.write(DateDiff("d",Date,"12/31/2002") & "<br />") document.write(DateDiff("n",Date,"12/31/2002"))
Uppgiften:
1/14/2002 11 351 505440
Exempel 2
Observera att i följande kod, date1>date2:
document.write(Date & "<br />") document.write(DateDiff("d","12/31/2002",Date))
Uppgiften:
1/14/2002 -351
Exempel 3
Hur många veckor (börjar på måndag), är kvar mellan den nuvarande datumen och 10/10/2002 document.write(Date & "<br />") document.write(DateDiff("w",Date,"10/10/2002",vbMonday))
Uppgiften:
1/14/2002 38